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3k^2-77k+280=0
a = 3; b = -77; c = +280;
Δ = b2-4ac
Δ = -772-4·3·280
Δ = 2569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-77)-\sqrt{2569}}{2*3}=\frac{77-\sqrt{2569}}{6} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-77)+\sqrt{2569}}{2*3}=\frac{77+\sqrt{2569}}{6} $
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